d^2+11d+20=0

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Solution for d^2+11d+20=0 equation: 



d^2+11d+20=0

a = 1; b = 11; c = +20;
Δ = b2-4ac
Δ = 112-4·1·20
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{41}}{2*1}=\frac{-11-\sqrt{41}}{2}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{41}}{2*1}=\frac{-11+\sqrt{41}}{2}
$

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